What are the solutions to the equation w^2+8w=2 ?

The solutions to the equation w^2+8w=2 are w=-4+3sqrt(2),w=-4-3sqrt(2)

Find the zeros of w^2+8w=2

The zeros of w^2+8w=2 are w=-4+3sqrt(2),w=-4-3sqrt(2)

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w^{2} + 8 w = 2

w = - 4 + 32, w = - 4 - 32

Decimal Notation

w = 0.24264 \dots, w = - 8.24264 \dots

Solution steps

w^{2} + 8 w = 2

Move

2

to the left side

w^{2} + 8 w - 2 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 2) = 62

w_{1, 2} = \frac{- 8 \pm 6 2}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 8 + 6 2}{2 \cdot 1}, w_{2} = \frac{- 8 - 6 2}{2 \cdot 1}

w = \frac{- 8 + 6 2}{2 \cdot 1} : - 4 + 32

w = \frac{- 8 - 6 2}{2 \cdot 1} : - 4 - 32

The solutions to the quadratic equation are:

w = - 4 + 32, w = - 4 - 32

\frac{1}{3} (3)^{3} - 4 (3)

1 - \frac{9}{10}

5 ∣ x - 2 ∣ > 10

49 x^{2} = 36

2 x^{2} + 2 x

What are the solutions to the equation w^2+8w=2 ?
The solutions to the equation w^2+8w=2 are w=-4+3sqrt(2),w=-4-3sqrt(2)
Find the zeros of w^2+8w=2
The zeros of w^2+8w=2 are w=-4+3sqrt(2),w=-4-3sqrt(2)