What are the solutions to the equation -24x^2-48x+360=0 ?

The solutions to the equation -24x^2-48x+360=0 are x=-5,x=3

Find the zeros of -24x^2-48x+360=0

The zeros of -24x^2-48x+360=0 are x=-5,x=3

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- 24 x^{2} - 48 x + 360 = 0

x = - 5, x = 3

Solution steps

- 24 x^{2} - 48 x + 360 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 ( - 24 ) \cdot 360}{2 ( - 24 )}

(- 48)^{2} - 4 (- 24) \cdot 360 = 192

x_{1, 2} = \frac{- ( - 48 ) \pm 192}{2 ( - 24 )}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 192}{2 ( - 24 )}, x_{2} = \frac{- ( - 48 ) - 192}{2 ( - 24 )}

x = \frac{- ( - 48 ) + 192}{2 ( - 24 )} : - 5

x = \frac{- ( - 48 ) - 192}{2 ( - 24 )} : 3

The solutions to the quadratic equation are:

x = - 5, x = 3

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What are the solutions to the equation -24x^2-48x+360=0 ?
The solutions to the equation -24x^2-48x+360=0 are x=-5,x=3
Find the zeros of -24x^2-48x+360=0
The zeros of -24x^2-48x+360=0 are x=-5,x=3