What are the solutions to the equation 5x^2-7x+2=0 ?

The solutions to the equation 5x^2-7x+2=0 are x=1,x= 2/5

Find the zeros of 5x^2-7x+2=0

The zeros of 5x^2-7x+2=0 are x=1,x= 2/5

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5 x^{2} - 7 x + 2 = 0

x = 1, x = \frac{2}{5}

Decimal Notation

x = 1, x = 0.4

Solution steps

5 x^{2} - 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 \cdot 2 = 3

x_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 5}, x_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 5}

x = \frac{- ( - 7 ) + 3}{2 \cdot 5} : 1

x = \frac{- ( - 7 ) - 3}{2 \cdot 5} : \frac{2}{5}

The solutions to the quadratic equation are:

x = 1, x = \frac{2}{5}

5 x^{2} - 3 x - 36

\frac{784}{16} = t^{2}

- 147 + 192 - 243

58 + 320 - 32

8 x^{2} - 24 x y + 18 y^{2}

What are the solutions to the equation 5x^2-7x+2=0 ?
The solutions to the equation 5x^2-7x+2=0 are x=1,x= 2/5
Find the zeros of 5x^2-7x+2=0
The zeros of 5x^2-7x+2=0 are x=1,x= 2/5