What are the solutions to the equation 2(x+2)^2-5=8 ?

The solutions to the equation 2(x+2)^2-5=8 are x=sqrt(13/2)-2,x=-sqrt(13/2)-2

Find the zeros of 2(x+2)^2-5=8

The zeros of 2(x+2)^2-5=8 are x=sqrt(13/2)-2,x=-sqrt(13/2)-2

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2 (x + 2)^{2} - 5 = 8

x = \frac{13}{2} - 2, x = - \frac{13}{2} - 2

Decimal Notation

x = 0.54950 \dots, x = - 4.54950 \dots

Solution steps

2 (x + 2)^{2} - 5 = 8

Move

5

to the right side

2 (x + 2)^{2} = 13

Divide both sides by

2

(x + 2)^{2} = \frac{13}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 2 = \frac{13}{2} : x = \frac{13}{2} - 2

Solve

x + 2 = - \frac{13}{2} : x = - \frac{13}{2} - 2

The solutions to the quadratic equation are:

x = \frac{13}{2} - 2, x = - \frac{13}{2} - 2

8 v - 4 (v + 8) = 8

a^{3} + 4 a

0 = x^{2} - 6 x + 8

95 = 183 t - 16 t^{2}

x^{2} - 4 x - 144 = 0

What are the solutions to the equation 2(x+2)^2-5=8 ?
The solutions to the equation 2(x+2)^2-5=8 are x=sqrt(13/2)-2,x=-sqrt(13/2)-2
Find the zeros of 2(x+2)^2-5=8
The zeros of 2(x+2)^2-5=8 are x=sqrt(13/2)-2,x=-sqrt(13/2)-2