What are the solutions to the equation n^2-14n-72=0 ?

The solutions to the equation n^2-14n-72=0 are n=18,n=-4

Find the zeros of n^2-14n-72=0

The zeros of n^2-14n-72=0 are n=18,n=-4

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n^{2} - 14 n - 72 = 0

n = 18, n = - 4

Solution steps

n^{2} - 14 n - 72 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot (- 72) = 22

n_{1, 2} = \frac{- ( - 14 ) \pm 22}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 14 ) + 22}{2 \cdot 1}, n_{2} = \frac{- ( - 14 ) - 22}{2 \cdot 1}

n = \frac{- ( - 14 ) + 22}{2 \cdot 1} : 18

n = \frac{- ( - 14 ) - 22}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

n = 18, n = - 4

\frac{2}{3} y + 1 \leq - y - \frac{5}{8}

\frac{7}{8} + \frac{7}{8}

z^{2} - 5 z - 24

- 5 a - 2 a^{2}

6 \cdot \frac{3}{8}

What are the solutions to the equation n^2-14n-72=0 ?
The solutions to the equation n^2-14n-72=0 are n=18,n=-4
Find the zeros of n^2-14n-72=0
The zeros of n^2-14n-72=0 are n=18,n=-4