What are the solutions to the equation 5y^2-8y=2 ?

The solutions to the equation 5y^2-8y=2 are y=(4+sqrt(26))/5 ,y=(4-sqrt(26))/5

Find the zeros of 5y^2-8y=2

The zeros of 5y^2-8y=2 are y=(4+sqrt(26))/5 ,y=(4-sqrt(26))/5

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5 y^{2} - 8 y = 2

y = \frac{4 + 26}{5}, y = \frac{4 - 26}{5}

Decimal Notation

y = 1.81980 \dots, y = - 0.21980 \dots

Solution steps

5 y^{2} - 8 y = 2

Move

2

to the left side

5 y^{2} - 8 y - 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 8)^{2} - 4 \cdot 5 (- 2) = 226

y_{1, 2} = \frac{- ( - 8 ) \pm 2 26}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 2 26}{2 \cdot 5}, y_{2} = \frac{- ( - 8 ) - 2 26}{2 \cdot 5}

y = \frac{- ( - 8 ) + 2 26}{2 \cdot 5} : \frac{4 + 26}{5}

y = \frac{- ( - 8 ) - 2 26}{2 \cdot 5} : \frac{4 - 26}{5}

The solutions to the quadratic equation are:

y = \frac{4 + 26}{5}, y = \frac{4 - 26}{5}

lo g_{b} (\frac{x ^{3} y}{z ^{6}})

10 x^{2} - x - 24 = 0

6 r^{2} + 6 r + 12 = 0

3 k + 12 \leq 6

\frac{5}{12}

What are the solutions to the equation 5y^2-8y=2 ?
The solutions to the equation 5y^2-8y=2 are y=(4+sqrt(26))/5 ,y=(4-sqrt(26))/5
Find the zeros of 5y^2-8y=2
The zeros of 5y^2-8y=2 are y=(4+sqrt(26))/5 ,y=(4-sqrt(26))/5