What are the solutions to the equation 9^2+7^2=c^2 ?

The solutions to the equation 9^2+7^2=c^2 are c=sqrt(130),c=-sqrt(130)

Find the zeros of 9^2+7^2=c^2

The zeros of 9^2+7^2=c^2 are c=sqrt(130),c=-sqrt(130)

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9^{2} + 7^{2} = c^{2}

c = 130, c = - 130

Decimal Notation

c = 11.40175 \dots, c = - 11.40175 \dots

Solution steps

9^{2} + 7^{2} = c^{2}

Switch sides

c^{2} = 9^{2} + 7^{2}

Simplify

9^{2} + 7^{2} : 130

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 130, c = - 130

5 a (- 3 b) (- 2 a^{2} b^{3})

\frac{k}{k + 1} + \frac{1}{( k + 1 ) ( k + 2 )}

53 = 8 + 0.07 t

\frac{\frac{10000}{\frac{1}{100}}}{1000}

\frac{\frac{1}{x} + \frac{1}{y}}{x - y}

What are the solutions to the equation 9^2+7^2=c^2 ?
The solutions to the equation 9^2+7^2=c^2 are c=sqrt(130),c=-sqrt(130)
Find the zeros of 9^2+7^2=c^2
The zeros of 9^2+7^2=c^2 are c=sqrt(130),c=-sqrt(130)