What is |((x^2+1))/2 |<3 ?

The solution to |((x^2+1))/2 |<3 is -sqrt(5)<x<sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

|((x^2+1))/2 |<3

\frac{( x ^{2} + 1 )}{2} < 3

- 5 < x < 5

Interval Notation

(- 5, 5)

Decimal Notation

- 2.23606 \dots < x < 2.23606 \dots

Solution steps

\frac{x ^{2} + 1}{2} < 3

Apply absolute rule: If

∣ u ∣ < a, a > 0

then

- a < u < a

- 3 < \frac{x ^{2} + 1}{2} < 3

\frac{x ^{2} + 1}{2} > - 3 and \frac{x ^{2} + 1}{2} < 3

True for all x and - 5 < x < 5

Merge Overlapping Intervals

- 5 < x < 5

(x + a)^{2} - 2 (x + a) (y + a) + (y + a)^{2}

0.59 = - 0.02746 x^{2} + 1.0052 x + 0.2694

p^{2} = 20 p

- 4 = \frac{3 x - 8}{5}

5 q^{2} - 5 q = 4 q^{2} - 7 q + 35

What is |((x^2+1))/2 |<3 ?
The solution to |((x^2+1))/2 |<3 is -sqrt(5)<x<sqrt(5)