What are the solutions to the equation 8q(q-2)+10=0 ?

The solutions to the equation 8q(q-2)+10=0 are q=1+i 1/2 ,q=1-i 1/2

Find the zeros of 8q(q-2)+10=0

The zeros of 8q(q-2)+10=0 are q=1+i 1/2 ,q=1-i 1/2

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8 q (q - 2) + 10 = 0

q = 1 + i \frac{1}{2}, q = 1 - i \frac{1}{2}

Solution steps

8 q (q - 2) + 10 = 0

Expand

8 q (q - 2) + 10 : 8 q^{2} - 16 q + 10

8 q^{2} - 16 q + 10 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 8 \cdot 10}{2 \cdot 8}

Simplify

(- 16)^{2} - 4 \cdot 8 \cdot 10 : 8 i

q_{1, 2} = \frac{- ( - 16 ) \pm 8 i}{2 \cdot 8}

Separate the solutions

q_{1} = \frac{- ( - 16 ) + 8 i}{2 \cdot 8}, q_{2} = \frac{- ( - 16 ) - 8 i}{2 \cdot 8}

q = \frac{- ( - 16 ) + 8 i}{2 \cdot 8} : 1 + i \frac{1}{2}

q = \frac{- ( - 16 ) - 8 i}{2 \cdot 8} : 1 - i \frac{1}{2}

The solutions to the quadratic equation are:

q = 1 + i \frac{1}{2}, q = 1 - i \frac{1}{2}

x^{2} + 5 x - 14 = 10

(\frac{2}{3})^{0}

1 - \frac{3}{5}

72 a^{6} b^{3} c^{2}

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What are the solutions to the equation 8q(q-2)+10=0 ?
The solutions to the equation 8q(q-2)+10=0 are q=1+i 1/2 ,q=1-i 1/2
Find the zeros of 8q(q-2)+10=0
The zeros of 8q(q-2)+10=0 are q=1+i 1/2 ,q=1-i 1/2