What are the solutions to the equation x^2+5x-14=10 ?

The solutions to the equation x^2+5x-14=10 are x=3,x=-8

Find the zeros of x^2+5x-14=10

The zeros of x^2+5x-14=10 are x=3,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 5 x - 14 = 10

x = 3, x = - 8

Solution steps

x^{2} + 5 x - 14 = 10

Move

10

to the left side

x^{2} + 5 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 24) = 11

x_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 11}{2 \cdot 1}, x_{2} = \frac{- 5 - 11}{2 \cdot 1}

x = \frac{- 5 + 11}{2 \cdot 1} : 3

x = \frac{- 5 - 11}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 3, x = - 8

(\frac{2}{3})^{0}

1 - \frac{3}{5}

72 a^{6} b^{3} c^{2}

- 22

What are the solutions to the equation x^2+5x-14=10 ?
The solutions to the equation x^2+5x-14=10 are x=3,x=-8
Find the zeros of x^2+5x-14=10
The zeros of x^2+5x-14=10 are x=3,x=-8