What are the solutions to the equation 6x^2-x-40=0 ?

The solutions to the equation 6x^2-x-40=0 are x= 8/3 ,x=-5/2

Find the zeros of 6x^2-x-40=0

The zeros of 6x^2-x-40=0 are x= 8/3 ,x=-5/2

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6 x^{2} - x - 40 = 0

x = \frac{8}{3}, x = - \frac{5}{2}

Decimal Notation

x = 2.66666 \dots, x = - 2.5

Solution steps

6 x^{2} - x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 6 ( - 40 )}{2 \cdot 6}

(- 1)^{2} - 4 \cdot 6 (- 40) = 31

x_{1, 2} = \frac{- ( - 1 ) \pm 31}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 31}{2 \cdot 6}, x_{2} = \frac{- ( - 1 ) - 31}{2 \cdot 6}

x = \frac{- ( - 1 ) + 31}{2 \cdot 6} : \frac{8}{3}

x = \frac{- ( - 1 ) - 31}{2 \cdot 6} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = - \frac{5}{2}

26 + 354

9 x - 8 = 2 x + 4 + 1

- (\frac{1}{2})^{- 1}

64 ab c - 80 ab + 16 a

\frac{( \frac{π}{2} )}{2 π}

What are the solutions to the equation 6x^2-x-40=0 ?
The solutions to the equation 6x^2-x-40=0 are x= 8/3 ,x=-5/2
Find the zeros of 6x^2-x-40=0
The zeros of 6x^2-x-40=0 are x= 8/3 ,x=-5/2