What are the solutions to the equation 3x^2+14x+15=0 ?

The solutions to the equation 3x^2+14x+15=0 are x=-5/3 ,x=-3

Find the zeros of 3x^2+14x+15=0

The zeros of 3x^2+14x+15=0 are x=-5/3 ,x=-3

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3 x^{2} + 14 x + 15 = 0

x = - \frac{5}{3}, x = - 3

Decimal Notation

x = - 1.66666 \dots, x = - 3

Solution steps

3 x^{2} + 14 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 \cdot 15}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 \cdot 15 = 4

x_{1, 2} = \frac{- 14 \pm 4}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 14 + 4}{2 \cdot 3}, x_{2} = \frac{- 14 - 4}{2 \cdot 3}

x = \frac{- 14 + 4}{2 \cdot 3} : - \frac{5}{3}

x = \frac{- 14 - 4}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = - \frac{5}{3}, x = - 3

6 y^{3} - 2 y^{2}

ln (\frac{6 x ^{3} e ^{2 x - 7}}{x ^{2} + 9})

∣ (7 - 3 x) ∣ < 2

\frac{x ^{2} - 4}{x ^{2} - 9} < 0

- 12 = (f - 6)

What are the solutions to the equation 3x^2+14x+15=0 ?
The solutions to the equation 3x^2+14x+15=0 are x=-5/3 ,x=-3
Find the zeros of 3x^2+14x+15=0
The zeros of 3x^2+14x+15=0 are x=-5/3 ,x=-3