What are the solutions to the equation 2x^2-40x=-172 ?

The solutions to the equation 2x^2-40x=-172 are x=10+sqrt(14),x=10-sqrt(14)

Find the zeros of 2x^2-40x=-172

The zeros of 2x^2-40x=-172 are x=10+sqrt(14),x=10-sqrt(14)

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2 x^{2} - 40 x = - 172

x = 10 + 14, x = 10 - 14

Decimal Notation

x = 13.74165 \dots, x = 6.25834 \dots

Solution steps

2 x^{2} - 40 x = - 172

Move

172

to the left side

2 x^{2} - 40 x + 172 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 2 \cdot 172}{2 \cdot 2}

(- 40)^{2} - 4 \cdot 2 \cdot 172 = 414

x_{1, 2} = \frac{- ( - 40 ) \pm 4 14}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 4 14}{2 \cdot 2}, x_{2} = \frac{- ( - 40 ) - 4 14}{2 \cdot 2}

x = \frac{- ( - 40 ) + 4 14}{2 \cdot 2} : 10 + 14

x = \frac{- ( - 40 ) - 4 14}{2 \cdot 2} : 10 - 14

The solutions to the quadratic equation are:

x = 10 + 14, x = 10 - 14

0. 5^{0}

a^{8} - 12 a^{4} + 36

- \frac{5}{2} \cdot 2

x^{\frac{1}{2}} \cdot x^{- 1}

(4 x + 1)^{2} = 64

What are the solutions to the equation 2x^2-40x=-172 ?
The solutions to the equation 2x^2-40x=-172 are x=10+sqrt(14),x=10-sqrt(14)
Find the zeros of 2x^2-40x=-172
The zeros of 2x^2-40x=-172 are x=10+sqrt(14),x=10-sqrt(14)