What are the solutions to the equation (4x+1)^2=64 ?

The solutions to the equation (4x+1)^2=64 are x= 7/4 ,x=-9/4

Find the zeros of (4x+1)^2=64

The zeros of (4x+1)^2=64 are x= 7/4 ,x=-9/4

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(4 x + 1)^{2} = 64

x = \frac{7}{4}, x = - \frac{9}{4}

Decimal Notation

x = 1.75, x = - 2.25

Solution steps

(4 x + 1)^{2} = 64

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 x + 1 = 64 : x = \frac{7}{4}

Solve

4 x + 1 = - 64 : x = - \frac{9}{4}

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = - \frac{9}{4}

x^{2} - 7 > 0

x^{2} = 5 x + 24

6 x + 5 = 1 + 2 (3 x + 2)

(a + b + c)^{2}

\frac{( 7 b - 14 )}{b} \leq 5

What are the solutions to the equation (4x+1)^2=64 ?
The solutions to the equation (4x+1)^2=64 are x= 7/4 ,x=-9/4
Find the zeros of (4x+1)^2=64
The zeros of (4x+1)^2=64 are x= 7/4 ,x=-9/4