What are the solutions to the equation y^2-12y=-23 ?

The solutions to the equation y^2-12y=-23 are y=6+sqrt(13),y=6-sqrt(13)

Find the zeros of y^2-12y=-23

The zeros of y^2-12y=-23 are y=6+sqrt(13),y=6-sqrt(13)

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y^{2} - 12 y = - 23

y = 6 + 13, y = 6 - 13

Decimal Notation

y = 9.60555 \dots, y = 2.39444 \dots

Solution steps

y^{2} - 12 y = - 23

Move

23

to the left side

y^{2} - 12 y + 23 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 23}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 23 = 213

y_{1, 2} = \frac{- ( - 12 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 12 ) + 2 13}{2 \cdot 1}, y_{2} = \frac{- ( - 12 ) - 2 13}{2 \cdot 1}

y = \frac{- ( - 12 ) + 2 13}{2 \cdot 1} : 6 + 13

y = \frac{- ( - 12 ) - 2 13}{2 \cdot 1} : 6 - 13

The solutions to the quadratic equation are:

y = 6 + 13, y = 6 - 13

\frac{5}{6} d - \frac{1}{5} = \frac{1}{2}

(a + bi) (a - bi)

\frac{2}{3} \leq \frac{4 x + 1}{5} < 4

2 (5 x + 4)^{2} - 40 = - 20

36 m^{2} - 24 m + 16 n^{2}

What are the solutions to the equation y^2-12y=-23 ?
The solutions to the equation y^2-12y=-23 are y=6+sqrt(13),y=6-sqrt(13)
Find the zeros of y^2-12y=-23
The zeros of y^2-12y=-23 are y=6+sqrt(13),y=6-sqrt(13)