What are the solutions to the equation (2x-1)^2=4 ?

The solutions to the equation (2x-1)^2=4 are x= 3/2 ,x=-1/2

Find the zeros of (2x-1)^2=4

The zeros of (2x-1)^2=4 are x= 3/2 ,x=-1/2

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(2 x - 1)^{2} = 4

x = \frac{3}{2}, x = - \frac{1}{2}

Decimal Notation

x = 1.5, x = - 0.5

Solution steps

(2 x - 1)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 1 = 4 : x = \frac{3}{2}

Solve

2 x - 1 = - 4 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - \frac{1}{2}

6 \leq \frac{2}{7} (x + 4)

27 u^{2} - 75

x + 5 = 3

(n + 2)!

8 y + 3 y = 44

What are the solutions to the equation (2x-1)^2=4 ?
The solutions to the equation (2x-1)^2=4 are x= 3/2 ,x=-1/2
Find the zeros of (2x-1)^2=4
The zeros of (2x-1)^2=4 are x= 3/2 ,x=-1/2