What is (4ab^{-5})^{-2} ?

The solution to (4ab^{-5})^{-2} is (b^{10})/(16a^2)

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simplify (4ab^{-5})^{-2}

simplify

(4 a b^{- 5})^{- 2}

\frac{b ^{10}}{16 a ^{2}}

Solution steps

(4 a b^{- 5})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(4 a b^{- 5})^{- 2} = \frac{1}{( 4 a b ^{- 5} ) ^{2}}

= \frac{1}{( 4 a b ^{- 5} ) ^{2}}

Simplify

(4 a b^{- 5})^{2} : \frac{16 a ^{2}}{b ^{10}}

= \frac{1}{\frac{16 a ^{2}}{b ^{10}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{b ^{10}}{16 a ^{2}}

x^{3} - 2 x^{2} - 35 x

\frac{1}{4} \cdot 52

4 x^{2} + 42 x = 2 x - 8

\frac{1}{2} r + 3 < - 6

\frac{3 ^{8}}{3 ^{2}}