What is ((x-5)(2x+3))/((x-1)^2)<= 0 ?

The solution to ((x-5)(2x+3))/((x-1)^2)<= 0 is -3/2 <= x<1\lor 1<x<= 5

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((x-5)(2x+3))/((x-1)^2)<= 0

\frac{( x - 5 ) ( 2 x + 3 )}{( x - 1 ) ^{2}} \leq 0

- \frac{3}{2} \leq x < 1 or 1 < x \leq 5

Interval Notation

[- \frac{3}{2}, 1) \cup (1, 5]

Decimal Notation

- 1.5 \leq x < 1 or 1 < x \leq 5

Solution steps

\frac{( x - 5 ) ( 2 x + 3 )}{( x - 1 ) ^{2}} \leq 0

Identify the intervals

- \frac{3}{2} \leq x < 1 or 1 < x \leq 5

64 u^{3} - v^{3}

2 m^{2} - 11 m + 15

- \frac{1}{4} (- 4)

x^{3} + 6 x^{2} - 16 x

(2)^{6}

What is ((x-5)(2x+3))/((x-1)^2)<= 0 ?
The solution to ((x-5)(2x+3))/((x-1)^2)<= 0 is -3/2 <= x<1\lor 1<x<= 5