What are the solutions to the equation (r+1)^2=0 ?

The solutions to the equation (r+1)^2=0 are r=-1

Find the zeros of (r+1)^2=0

The zeros of (r+1)^2=0 are r=-1

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(r + 1)^{2} = 0

r = - 1

Solution steps

(r + 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

r + 1 = 0 : r = - 1

The solution to the quadratic equation is:

r = - 1

x + 1 < 34

\frac{5}{8} = \frac{x}{7}

27 - a^{3}

\frac{64 x ^{2} - 49 y ^{2}}{8 x - 7 y}

x = \frac{150 ( 1500 )}{( \frac{π 1 8 ^{2}}{4} ) 120}

What are the solutions to the equation (r+1)^2=0 ?
The solutions to the equation (r+1)^2=0 are r=-1
Find the zeros of (r+1)^2=0
The zeros of (r+1)^2=0 are r=-1