What are the solutions to the equation x^2-14x+65=0 ?

The solutions to the equation x^2-14x+65=0 are x=7+4i,x=7-4i

Find the zeros of x^2-14x+65=0

The zeros of x^2-14x+65=0 are x=7+4i,x=7-4i

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x^{2} - 14 x + 65 = 0

x = 7 + 4 i, x = 7 - 4 i

Solution steps

x^{2} - 14 x + 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 65}{2 \cdot 1}

Simplify

(- 14)^{2} - 4 \cdot 1 \cdot 65 : 8 i

x_{1, 2} = \frac{- ( - 14 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 8 i}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 8 i}{2 \cdot 1}

x = \frac{- ( - 14 ) + 8 i}{2 \cdot 1} : 7 + 4 i

x = \frac{- ( - 14 ) - 8 i}{2 \cdot 1} : 7 - 4 i

The solutions to the quadratic equation are:

x = 7 + 4 i, x = 7 - 4 i

4 x^{4} + 5 x^{2} - 18 x^{3} y^{3}

24 w - 32 x + 72 y

7 x + 1 \leq 9

\frac{2 x y ^{- 3}}{x ^{- 2} y ^{4}}

\frac{6.5522 + 2.23}{0.1234}

What are the solutions to the equation x^2-14x+65=0 ?
The solutions to the equation x^2-14x+65=0 are x=7+4i,x=7-4i
Find the zeros of x^2-14x+65=0
The zeros of x^2-14x+65=0 are x=7+4i,x=7-4i