What are the solutions to the equation x^2+7=6x ?

The solutions to the equation x^2+7=6x are x=3+sqrt(2),x=3-sqrt(2)

Find the zeros of x^2+7=6x

The zeros of x^2+7=6x are x=3+sqrt(2),x=3-sqrt(2)

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x^{2} + 7 = 6 x

x = 3 + 2, x = 3 - 2

Decimal Notation

x = 4.41421 \dots, x = 1.58578 \dots

Solution steps

x^{2} + 7 = 6 x

Move

6 x

to the left side

x^{2} + 7 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 7 = 22

x_{1, 2} = \frac{- ( - 6 ) \pm 2 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 2}{2 \cdot 1} : 3 + 2

x = \frac{- ( - 6 ) - 2 2}{2 \cdot 1} : 3 - 2

The solutions to the quadratic equation are:

x = 3 + 2, x = 3 - 2

8 (x - 9) - 9 (x - 8) = x + 8 - (x - 2)

5 (n + 1)^{2} = 40

(\frac{- 2 x ^{- 2} y ^{4}}{x ^{2} y ^{6}})^{3}

(3 x - 2 y)^{2} - (2 x - 3 y)^{2}

6 + 2 n = 3

What are the solutions to the equation x^2+7=6x ?
The solutions to the equation x^2+7=6x are x=3+sqrt(2),x=3-sqrt(2)
Find the zeros of x^2+7=6x
The zeros of x^2+7=6x are x=3+sqrt(2),x=3-sqrt(2)