What are the solutions to the equation 2x^2+8x-5=0 ?

The solutions to the equation 2x^2+8x-5=0 are x=(-4+sqrt(26))/2 ,x=-(4+sqrt(26))/2

Find the zeros of 2x^2+8x-5=0

The zeros of 2x^2+8x-5=0 are x=(-4+sqrt(26))/2 ,x=-(4+sqrt(26))/2

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2 x^{2} + 8 x - 5 = 0

x = \frac{- 4 + 26}{2}, x = - \frac{4 + 26}{2}

Decimal Notation

x = 0.54950 \dots, x = - 4.54950 \dots

Solution steps

2 x^{2} + 8 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 5) = 226

x_{1, 2} = \frac{- 8 \pm 2 26}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 2 26}{2 \cdot 2}, x_{2} = \frac{- 8 - 2 26}{2 \cdot 2}

x = \frac{- 8 + 2 26}{2 \cdot 2} : \frac{- 4 + 26}{2}

x = \frac{- 8 - 2 26}{2 \cdot 2} : - \frac{4 + 26}{2}

The solutions to the quadratic equation are:

x = \frac{- 4 + 26}{2}, x = - \frac{4 + 26}{2}

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\frac{125 y ^{2}}{10 x y}

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x^{2} - 18 x + 14 < 0

3 r^{5} + 3 r^{4} - 90 r^{3}

What are the solutions to the equation 2x^2+8x-5=0 ?
The solutions to the equation 2x^2+8x-5=0 are x=(-4+sqrt(26))/2 ,x=-(4+sqrt(26))/2
Find the zeros of 2x^2+8x-5=0
The zeros of 2x^2+8x-5=0 are x=(-4+sqrt(26))/2 ,x=-(4+sqrt(26))/2