What is factor 2j^2+9j+7 ?

The solution to factor 2j^2+9j+7 is (j+1)(2j+7)

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factor 2j^2+9j+7

factor

2 j^{2} + 9 j + 7

(j + 1) (2 j + 7)

Solution steps

2 j^{2} + 9 j + 7

Break the expression into groups

= (2 j^{2} + 2 j) + (7 j + 7)

Factor out

2 j

from

2 j^{2} + 2 j : 2 j (j + 1)

Factor out

7

from

7 j + 7 : 7 (j + 1)

= 2 j (j + 1) + 7 (j + 1)

Factor out common term

j + 1

= (j + 1) (2 j + 7)

x - 7.6 (0.9 x + 1) \leq 5.6 (1 + 1.1 x)

\frac{1}{x - 4} \geq \frac{3}{x + 1}

2 x^{2} + 8 x - 5 = 0

\frac{6 x + 1}{4 x + 1} + \frac{4 x + 3}{2 x - 3} \leq 0