What are the solutions to the equation (3+2-x)^2=4 ?

The solutions to the equation (3+2-x)^2=4 are x=3,x=7

Find the zeros of (3+2-x)^2=4

The zeros of (3+2-x)^2=4 are x=3,x=7

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(3 + 2 - x)^{2} = 4

x = 3, x = 7

Solution steps

(3 + 2 - x)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 + 2 - x = 4 : x = 3

Solve

3 + 2 - x = - 4 : x = 7

The solutions to the quadratic equation are:

x = 3, x = 7

∣ 9 x - 4 ∣ = ∣ - 5 ∣

4 x - 3 > x + 6

(- 2 a b^{3}) (- 3 a^{2} b^{5})

- 7 + (- 8 z + 2) = (7 z + 5) + 1

\frac{1}{2} x - \frac{5}{4} + 2 x = \frac{5}{6} + x

What are the solutions to the equation (3+2-x)^2=4 ?
The solutions to the equation (3+2-x)^2=4 are x=3,x=7
Find the zeros of (3+2-x)^2=4
The zeros of (3+2-x)^2=4 are x=3,x=7