What are the solutions to the equation 4x^2+16x=20 ?

The solutions to the equation 4x^2+16x=20 are x=1,x=-5

Find the zeros of 4x^2+16x=20

The zeros of 4x^2+16x=20 are x=1,x=-5

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4 x^{2} + 16 x = 20

x = 1, x = - 5

Solution steps

4 x^{2} + 16 x = 20

Move

20

to the left side

4 x^{2} + 16 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 ( - 20 )}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 (- 20) = 24

x_{1, 2} = \frac{- 16 \pm 24}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 24}{2 \cdot 4}, x_{2} = \frac{- 16 - 24}{2 \cdot 4}

x = \frac{- 16 + 24}{2 \cdot 4} : 1

x = \frac{- 16 - 24}{2 \cdot 4} : - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

- 8 (n - 83) = - 40

(2^{- 4} \cdot z^{- 3})^{5}

\frac{- 15 k ^{2}}{15 k ^{3} + 45 k ^{2}}

- 3 x + 2 > 17 or - 5 x + 3 \leq 13

8 x + 4 (- 6 x + 4) = - 6 - 5 x

What are the solutions to the equation 4x^2+16x=20 ?
The solutions to the equation 4x^2+16x=20 are x=1,x=-5
Find the zeros of 4x^2+16x=20
The zeros of 4x^2+16x=20 are x=1,x=-5