What is (1-x/y)/(\frac{x^2){y^2}-1} ?

The solution to (1-x/y)/(\frac{x^2){y^2}-1} is -y/(x+y)

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simplify (1-x/y)/(\frac{x^2){y^2}-1}

simplify

\frac{1 - \frac{x}{y}}{\frac{x ^{2}}{y ^{2}} - 1}

- \frac{y}{x + y}

Solution steps

\frac{1 - \frac{x}{y}}{\frac{x ^{2}}{y ^{2}} - 1}

Join

1 - \frac{x}{y} : \frac{y - x}{y}

= \frac{\frac{y - x}{y}}{\frac{x ^{2}}{y ^{2}} - 1}

Join

\frac{x ^{2}}{y ^{2}} - 1 : \frac{- y ^{2} + x ^{2}}{y ^{2}}

= \frac{\frac{y - x}{y}}{\frac{- y ^{2} + x ^{2}}{y ^{2}}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( y - x ) y ^{2}}{y ( - y ^{2} + x ^{2} )}

Cancel

\frac{( y - x ) y ^{2}}{y ( - y ^{2} + x ^{2} )} : - \frac{y}{x + y}

= - \frac{y}{x + y}

\frac{1}{8} - \frac{1}{4}

\frac{5 ^{2} y ^{- 10}}{5 ^{- 1} z ^{0} x ^{- 5}}

7 - 4 (d - 3) = 23

(\frac{5 2}{2})^{2}

\frac{x ^{2} - 1}{x - 1}

What is (1-x/y)/(\frac{x^2){y^2}-1} ?
The solution to (1-x/y)/(\frac{x^2){y^2}-1} is -y/(x+y)