What are the solutions to the equation 3x^2-4=0 ?

The solutions to the equation 3x^2-4=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))

Find the zeros of 3x^2-4=0

The zeros of 3x^2-4=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))

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3 x^{2} - 4 = 0

x = \frac{2}{3}, x = - \frac{2}{3}

Decimal Notation

x = 1.15470 \dots, x = - 1.15470 \dots

Solution steps

3 x^{2} - 4 = 0

Move

4

to the right side

3 x^{2} = 4

Divide both sides by

3

x^{2} = \frac{4}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{4}{3}, x = - \frac{4}{3}

\frac{4}{3} = \frac{2}{3}

- \frac{4}{3} = - \frac{2}{3}

x = \frac{2}{3}, x = - \frac{2}{3}

x^{8} - 256 x^{4}

3 = a (1 - 3)^{2} + (- 5)

(7)^{- 3}

\frac{2}{15} b - \frac{4}{5} < \frac{2}{3}

\frac{8}{8}

What are the solutions to the equation 3x^2-4=0 ?
The solutions to the equation 3x^2-4=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))
Find the zeros of 3x^2-4=0
The zeros of 3x^2-4=0 are x= 2/(sqrt(3)),x=-2/(sqrt(3))