vereinfachen (x^{4/3}x^{2/3})^{1/3}

Lösung

vereinfachen

(x^{\frac{4}{3}} x^{\frac{2}{3}})^{\frac{1}{3}}

x^{\frac{2}{3}}

Schritte zur Lösung

(x^{\frac{4}{3}} x^{\frac{2}{3}})^{\frac{1}{3}}

Wende Exponentenregel an:

(a \cdot b)^{n} = a^{n} b^{n}

(x^{\frac{4}{3}} x^{\frac{2}{3}})^{\frac{1}{3}} = (x^{\frac{4}{3}})^{\frac{1}{3}} (x^{\frac{2}{3}})^{\frac{1}{3}}

= (x^{\frac{4}{3}})^{\frac{1}{3}} (x^{\frac{2}{3}})^{\frac{1}{3}}

Vereinfache

(x^{\frac{4}{3}})^{\frac{1}{3}} : x^{\frac{4}{9}}

= x^{\frac{4}{9}} (x^{\frac{2}{3}})^{\frac{1}{3}}

Vereinfache

(x^{\frac{2}{3}})^{\frac{1}{3}} : x^{\frac{2}{9}}

= x^{\frac{4}{9}} x^{\frac{2}{9}}

Wende Exponentenregel an:

a^{b} \cdot a^{c} = a^{b + c}

x^{\frac{4}{9}} x^{\frac{2}{9}} = x^{\frac{4}{9} + \frac{2}{9}}

= x^{\frac{4}{9} + \frac{2}{9}}

Füge

\frac{4}{9} + \frac{2}{9}

zusammen:

\frac{2}{3}

= x^{\frac{2}{3}}

s im pl i f y \frac{a}{a - b} - \frac{2 ab}{a ^{2} - b ^{2}}

- 4 (x - 3) \geq 2 x + 5

6 (2 x - 1)^{2} + 2 = - 7 (2 x - 1)

6 (x + 4) + 1 = x + 5

f a c t or x^{2} - 4 x y - 77 y^{2}