w^2+3w-28=0

解

w^{2} + 3 w - 28 = 0

w = 4, w = - 7

解答ステップ

w^{2} + 3 w - 28 = 0

解くとthe二次式

w_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 28) = 11

w_{1, 2} = \frac{- 3 \pm 11}{2 \cdot 1}

解を分離する

w_{1} = \frac{- 3 + 11}{2 \cdot 1}, w_{2} = \frac{- 3 - 11}{2 \cdot 1}

w = \frac{- 3 + 11}{2 \cdot 1} : 4

w = \frac{- 3 - 11}{2 \cdot 1} : - 7

二次equationの解:

w = 4, w = - 7