What is (3m-9)/(4m+8)*(m^2+5m+6)/(m^2-9) ?

The solution to (3m-9)/(4m+8)*(m^2+5m+6)/(m^2-9) is 3/4

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simplify (3m-9)/(4m+8)*(m^2+5m+6)/(m^2-9)

simplify

\frac{3 m - 9}{4 m + 8} \cdot \frac{m ^{2} + 5 m + 6}{m ^{2} - 9}

\frac{3}{4}

Decimal Notation

0.75

Solution steps

\frac{3 m - 9}{4 m + 8} \cdot \frac{m ^{2} + 5 m + 6}{m ^{2} - 9}

Cancel

\frac{m ^{2} + 5 m + 6}{m ^{2} - 9} : \frac{m + 2}{m - 3}

= \frac{3 m - 9}{4 m + 8} \cdot \frac{m + 2}{m - 3}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( 3 m - 9 ) ( m + 2 )}{( 4 m + 8 ) ( m - 3 )}

Factor

3 m - 9 : 3 (m - 3)

= \frac{3 ( m - 3 ) ( m + 2 )}{( 4 m + 8 ) ( m - 3 )}

Cancel the common factor:

m - 3

= \frac{3 ( m + 2 )}{4 m + 8}

Factor

4 m + 8 : 4 (m + 2)

= \frac{3 ( m + 2 )}{4 ( m + 2 )}

Cancel the common factor:

m + 2

= \frac{3}{4}

\frac{3 i}{5 - 2 i}

\frac{10}{x + 2} \leq 5

4 r^{2} - 9

\frac{y}{4} - \frac{y - 1}{2} \geq 3

4 + ∣ 1 + 2 x ∣ = 10

What is (3m-9)/(4m+8)*(m^2+5m+6)/(m^2-9) ?
The solution to (3m-9)/(4m+8)*(m^2+5m+6)/(m^2-9) is 3/4