What are the solutions to the equation (x+3)^2+5=0 ?

The solutions to the equation (x+3)^2+5=0 are x=sqrt(5)i-3,x=-sqrt(5)i-3

Find the zeros of (x+3)^2+5=0

The zeros of (x+3)^2+5=0 are x=sqrt(5)i-3,x=-sqrt(5)i-3

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(x + 3)^{2} + 5 = 0

x = 5 i - 3, x = - 5 i - 3

Solution steps

(x + 3)^{2} + 5 = 0

Move

5

to the right side

(x + 3)^{2} = - 5

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = - 5 : x = 5 i - 3

Solve

x + 3 = - - 5 : x = - 5 i - 3

The solutions to the quadratic equation are:

x = 5 i - 3, x = - 5 i - 3

8 - ∣ 3 x + 9 ∣ = 5

\frac{1}{7} x \geq 2

(3 x + 1) (x - 2) > (x - 3) (3 x + 4)

26.5 + 0.15 = 14.5 \cdot 0.25

- 4 \leq x^{2} + 3 x - 4 \leq 6

What are the solutions to the equation (x+3)^2+5=0 ?
The solutions to the equation (x+3)^2+5=0 are x=sqrt(5)i-3,x=-sqrt(5)i-3
Find the zeros of (x+3)^2+5=0
The zeros of (x+3)^2+5=0 are x=sqrt(5)i-3,x=-sqrt(5)i-3