What is 6(-2)^2+6(-2)-12 ?

The solution to 6(-2)^2+6(-2)-12 is 0

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6(-2)^2+6(-2)-12

6 (- 2)^{2} + 6 (- 2) - 12

0

Solution steps

6 (- 2)^{2} + 6 (- 2) - 12

Follow the PEMDAS order of operations

Calculate exponents

(- 2)^{2} : 4

= 6 \cdot 4 + 6 (- 2) - 12

Multiply and divide (left to right)

6 \cdot 4 : 24

= 24 + 6 (- 2) - 12

Multiply and divide (left to right)

6 (- 2) : - 12

= 24 - 12 - 12

Add and subtract (left to right)

24 - 12 - 12 : 0

= 0

\frac{2 x - 5}{3} - \frac{5 x - 3}{4} + 2 + \frac{2}{3} = 0

x^{2} - 7 x y + 6 y^{2}

6 (\frac{1}{3})^{1}

\frac{3}{4} \cdot 8

4 (u + 1) + u = 8 (u - 1) + 6