What are the solutions to the equation r^2-9r+18=0 ?

The solutions to the equation r^2-9r+18=0 are r=6,r=3

Find the zeros of r^2-9r+18=0

The zeros of r^2-9r+18=0 are r=6,r=3

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r^{2} - 9 r + 18 = 0

r = 6, r = 3

Solution steps

r^{2} - 9 r + 18 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

r_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, r_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

r = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

r = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

r = 6, r = 3

(x + 9)^{2} (x - 2) < 0

x^{2} + 5 x - 14 \leq 2 x - 4

- 12 < \frac{6 x - 24}{3} < 4

\frac{6}{10}

x \cdot x^{- \frac{1}{2}}

What are the solutions to the equation r^2-9r+18=0 ?
The solutions to the equation r^2-9r+18=0 are r=6,r=3
Find the zeros of r^2-9r+18=0
The zeros of r^2-9r+18=0 are r=6,r=3