What are the solutions to the equation 7-2x^2=-7 ?

The solutions to the equation 7-2x^2=-7 are x=sqrt(7),x=-sqrt(7)

Find the zeros of 7-2x^2=-7

The zeros of 7-2x^2=-7 are x=sqrt(7),x=-sqrt(7)

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7 - 2 x^{2} = - 7

x = 7, x = - 7

Decimal Notation

x = 2.64575 \dots, x = - 2.64575 \dots

Solution steps

7 - 2 x^{2} = - 7

Move

7

to the right side

- 2 x^{2} = - 14

Divide both sides by

- 2

x^{2} = 7

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 7, x = - 7

(8 x^{6})^{- \frac{2}{3}}

4 (u + 2) - u = 2 (u - 1) + 9

4 x + 1 < 2 x + 3

\frac{3 π}{2} + \frac{π}{2}

2^{2 n + 2}

What are the solutions to the equation 7-2x^2=-7 ?
The solutions to the equation 7-2x^2=-7 are x=sqrt(7),x=-sqrt(7)
Find the zeros of 7-2x^2=-7
The zeros of 7-2x^2=-7 are x=sqrt(7),x=-sqrt(7)