What are the solutions to the equation x^2+20x+75=0 ?

The solutions to the equation x^2+20x+75=0 are x=-5,x=-15

Find the zeros of x^2+20x+75=0

The zeros of x^2+20x+75=0 are x=-5,x=-15

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x^{2} + 20 x + 75 = 0

x = - 5, x = - 15

Solution steps

x^{2} + 20 x + 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 75}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 75 = 10

x_{1, 2} = \frac{- 20 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 10}{2 \cdot 1}, x_{2} = \frac{- 20 - 10}{2 \cdot 1}

x = \frac{- 20 + 10}{2 \cdot 1} : - 5

x = \frac{- 20 - 10}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = - 5, x = - 15

4 + 3 u = - 11

29 x - 25 < 91

2 y^{2} - 3 y - 2

\frac{1200}{\frac{π}{4} \cdot 0. 6 ^{2}}

What are the solutions to the equation x^2+20x+75=0 ?
The solutions to the equation x^2+20x+75=0 are x=-5,x=-15
Find the zeros of x^2+20x+75=0
The zeros of x^2+20x+75=0 are x=-5,x=-15