What are the solutions to the equation 2x(x-3)=4x^2-7x ?

The solutions to the equation 2x(x-3)=4x^2-7x are x=0,x= 1/2

Find the zeros of 2x(x-3)=4x^2-7x

The zeros of 2x(x-3)=4x^2-7x are x=0,x= 1/2

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2 x (x - 3) = 4 x^{2} - 7 x

x = 0, x = \frac{1}{2}

Decimal Notation

x = 0, x = 0.5

Solution steps

2 x (x - 3) = 4 x^{2} - 7 x

Expand

2 x (x - 3) : 2 x^{2} - 6 x

2 x^{2} - 6 x = 4 x^{2} - 7 x

Move

7 x

to the left side

2 x^{2} + x = 4 x^{2}

Move

4 x^{2}

to the left side

- 2 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

1^{2} - 4 (- 2) \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 ( - 2 )}, x_{2} = \frac{- 1 - 1}{2 ( - 2 )}

x = \frac{- 1 + 1}{2 ( - 2 )} : 0

x = \frac{- 1 - 1}{2 ( - 2 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{2}

2 x + 7 = 3

(\frac{4 a ^{2} b}{a ^{3} b ^{2}}) (\frac{5 a ^{2} b}{2 b ^{4}})

5 \cdot 7

- x^{2} - 2 x + 8 = 0

x^{2} + 20 x + 75 = 0

What are the solutions to the equation 2x(x-3)=4x^2-7x ?
The solutions to the equation 2x(x-3)=4x^2-7x are x=0,x= 1/2
Find the zeros of 2x(x-3)=4x^2-7x
The zeros of 2x(x-3)=4x^2-7x are x=0,x= 1/2