What are the solutions to the equation x^2+x-6=0 ?

The solutions to the equation x^2+x-6=0 are x=2,x=-3

Find the zeros of x^2+x-6=0

The zeros of x^2+x-6=0 are x=2,x=-3

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x^{2} + x - 6 = 0

x = 2, x = - 3

Solution steps

x^{2} + x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 5}{2 \cdot 1}, x_{2} = \frac{- 1 - 5}{2 \cdot 1}

x = \frac{- 1 + 5}{2 \cdot 1} : 2

x = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 2, x = - 3

x + \frac{2}{x - 1} \geq 4

\frac{2 y}{2 x y}

\frac{x - 2}{x ^{2} - 3 x - 10} \geq 0

\frac{8 x ^{3} y ^{- 5}}{4 x ^{- 1} y ^{2}}

x - 7 < 3 (x + 1)

What are the solutions to the equation x^2+x-6=0 ?
The solutions to the equation x^2+x-6=0 are x=2,x=-3
Find the zeros of x^2+x-6=0
The zeros of x^2+x-6=0 are x=2,x=-3