What are the solutions to the equation x+10=x^2+x+1 ?

The solutions to the equation x+10=x^2+x+1 are x=3,x=-3

Find the zeros of x+10=x^2+x+1

The zeros of x+10=x^2+x+1 are x=3,x=-3

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x + 10 = x^{2} + x + 1

x = 3, x = - 3

Solution steps

x + 10 = x^{2} + x + 1

Switch sides

x^{2} + x + 1 = x + 10

Move

1

to the right side

x^{2} + x = x + 9

Move

x

to the left side

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

(x + h)^{- 2}

4 x^{2} - 6 x

2 - 8 x^{2}

\frac{10 !}{( 10 - 2 ) !}

\frac{x}{25} = - 25

What are the solutions to the equation x+10=x^2+x+1 ?
The solutions to the equation x+10=x^2+x+1 are x=3,x=-3
Find the zeros of x+10=x^2+x+1
The zeros of x+10=x^2+x+1 are x=3,x=-3