What are the solutions to the equation 4x-8x^2=0 ?

The solutions to the equation 4x-8x^2=0 are x=0,x= 1/2

Find the zeros of 4x-8x^2=0

The zeros of 4x-8x^2=0 are x=0,x= 1/2

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4 x - 8 x^{2} = 0

x = 0, x = \frac{1}{2}

Decimal Notation

x = 0, x = 0.5

Solution steps

4 x - 8 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 8 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 8 ) \cdot 0}{2 ( - 8 )}

4^{2} - 4 (- 8) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 8 )}, x_{2} = \frac{- 4 - 4}{2 ( - 8 )}

x = \frac{- 4 + 4}{2 ( - 8 )} : 0

x = \frac{- 4 - 4}{2 ( - 8 )} : \frac{1}{2}

The solutions to the quadratic equation are:

x = 0, x = \frac{1}{2}

2 d^{2} + 9 d + 9

x^{2} = \frac{25}{81}

6 x^{2} + 30 x - 84

\frac{1 - a ^{2}}{4 a + 8 b} \times \frac{a ^{2} + 4 ab + 4 b ^{2}}{3 - 3 a}

0 = 200 - 32 t

What are the solutions to the equation 4x-8x^2=0 ?
The solutions to the equation 4x-8x^2=0 are x=0,x= 1/2
Find the zeros of 4x-8x^2=0
The zeros of 4x-8x^2=0 are x=0,x= 1/2