What are the solutions to the equation 18a^2+10a=-11a+4 ?

The solutions to the equation 18a^2+10a=-11a+4 are a= 1/6 ,a=-4/3

Find the zeros of 18a^2+10a=-11a+4

The zeros of 18a^2+10a=-11a+4 are a= 1/6 ,a=-4/3

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18 a^{2} + 10 a = - 11 a + 4

a = \frac{1}{6}, a = - \frac{4}{3}

Decimal Notation

a = 0.16666 \dots, a = - 1.33333 \dots

Solution steps

18 a^{2} + 10 a = - 11 a + 4

Move

4

to the left side

18 a^{2} + 10 a - 4 = - 11 a

Move

11 a

to the left side

18 a^{2} + 21 a - 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 18 ( - 4 )}{2 \cdot 18}

2 1^{2} - 4 \cdot 18 (- 4) = 27

a_{1, 2} = \frac{- 21 \pm 27}{2 \cdot 18}

Separate the solutions

a_{1} = \frac{- 21 + 27}{2 \cdot 18}, a_{2} = \frac{- 21 - 27}{2 \cdot 18}

a = \frac{- 21 + 27}{2 \cdot 18} : \frac{1}{6}

a = \frac{- 21 - 27}{2 \cdot 18} : - \frac{4}{3}

The solutions to the quadratic equation are:

a = \frac{1}{6}, a = - \frac{4}{3}

lo g_{5} (- 25)

x^{2} + 18 x + 70 = 0

4 x^{2} - 40 x + 100

y^{2} - 12 y + 20

2 x^{2} + 7 x - 9

What are the solutions to the equation 18a^2+10a=-11a+4 ?
The solutions to the equation 18a^2+10a=-11a+4 are a= 1/6 ,a=-4/3
Find the zeros of 18a^2+10a=-11a+4
The zeros of 18a^2+10a=-11a+4 are a= 1/6 ,a=-4/3