What are the solutions to the equation c^2+9c+18=0 ?

The solutions to the equation c^2+9c+18=0 are c=-3,c=-6

Find the zeros of c^2+9c+18=0

The zeros of c^2+9c+18=0 are c=-3,c=-6

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c^{2} + 9 c + 18 = 0

c = - 3, c = - 6

Solution steps

c^{2} + 9 c + 18 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 18 = 3

c_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 9 + 3}{2 \cdot 1}, c_{2} = \frac{- 9 - 3}{2 \cdot 1}

c = \frac{- 9 + 3}{2 \cdot 1} : - 3

c = \frac{- 9 - 3}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

c = - 3, c = - 6

n^{2} = 100

\frac{3}{4} (8)

- \frac{2}{2} - \frac{2}{2}

8000

- 7 x - 5 = - 4 x - 29

What are the solutions to the equation c^2+9c+18=0 ?
The solutions to the equation c^2+9c+18=0 are c=-3,c=-6
Find the zeros of c^2+9c+18=0
The zeros of c^2+9c+18=0 are c=-3,c=-6