What are the solutions to the equation 4x^2+9x^2=36 ?

The solutions to the equation 4x^2+9x^2=36 are x= 6/(sqrt(13)),x=-6/(sqrt(13))

Find the zeros of 4x^2+9x^2=36

The zeros of 4x^2+9x^2=36 are x= 6/(sqrt(13)),x=-6/(sqrt(13))

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4 x^{2} + 9 x^{2} = 36

x = \frac{6}{13}, x = - \frac{6}{13}

Decimal Notation

x = 1.66410 \dots, x = - 1.66410 \dots

Solution steps

4 x^{2} + 9 x^{2} = 36

Add similar elements:

4 x^{2} + 9 x^{2} = 13 x^{2}

13 x^{2} = 36

Divide both sides by

13

x^{2} = \frac{36}{13}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{36}{13}, x = - \frac{36}{13}

\frac{36}{13} = \frac{6}{13}

- \frac{36}{13} = - \frac{6}{13}

x = \frac{6}{13}, x = - \frac{6}{13}

a x + a y + a z

\frac{45 p ^{3} s t ^{2}}{9 p ^{2} s ^{3} t}

- 4 (v - 2) = - 4 (v - 8) - 8 v

X^{2} = 49

x^{2} + 20 x + 100 = 50

What are the solutions to the equation 4x^2+9x^2=36 ?
The solutions to the equation 4x^2+9x^2=36 are x= 6/(sqrt(13)),x=-6/(sqrt(13))
Find the zeros of 4x^2+9x^2=36
The zeros of 4x^2+9x^2=36 are x= 6/(sqrt(13)),x=-6/(sqrt(13))