What are the solutions to the equation (4n-1)^2=16 ?

The solutions to the equation (4n-1)^2=16 are n= 5/4 ,n=-3/4

Find the zeros of (4n-1)^2=16

The zeros of (4n-1)^2=16 are n= 5/4 ,n=-3/4

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(4 n - 1)^{2} = 16

n = \frac{5}{4}, n = - \frac{3}{4}

Decimal Notation

n = 1.25, n = - 0.75

Solution steps

(4 n - 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 n - 1 = 16 : n = \frac{5}{4}

Solve

4 n - 1 = - 16 : n = - \frac{3}{4}

The solutions to the quadratic equation are:

n = \frac{5}{4}, n = - \frac{3}{4}

7^{2} + b^{2} = 1 0^{2}

x - 1.4 = 0.6

4 x^{2} + 36 x y + 81 y^{2}

z^{2} + z + 25 = 0

\frac{( \frac{3}{2} )}{\frac{1}{2}}

What are the solutions to the equation (4n-1)^2=16 ?
The solutions to the equation (4n-1)^2=16 are n= 5/4 ,n=-3/4
Find the zeros of (4n-1)^2=16
The zeros of (4n-1)^2=16 are n= 5/4 ,n=-3/4