What are the solutions to the equation 4x^2-12x=-13 ?

The solutions to the equation 4x^2-12x=-13 are x= 3/2+i,x= 3/2-i

Find the zeros of 4x^2-12x=-13

The zeros of 4x^2-12x=-13 are x= 3/2+i,x= 3/2-i

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4 x^{2} - 12 x = - 13

x = \frac{3}{2} + i, x = \frac{3}{2} - i

Solution steps

4 x^{2} - 12 x = - 13

Move

13

to the left side

4 x^{2} - 12 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 13}{2 \cdot 4}

Simplify

(- 12)^{2} - 4 \cdot 4 \cdot 13 : 8 i

x_{1, 2} = \frac{- ( - 12 ) \pm 8 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8 i}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 8 i}{2 \cdot 4}

x = \frac{- ( - 12 ) + 8 i}{2 \cdot 4} : \frac{3}{2} + i

x = \frac{- ( - 12 ) - 8 i}{2 \cdot 4} : \frac{3}{2} - i

The solutions to the quadratic equation are:

x = \frac{3}{2} + i, x = \frac{3}{2} - i

\frac{x}{5} - 3 = 8

2 (2 x^{2} - 3 x) \geq 9

4 x - (7 x + 3) \leq 8 x + 2 (x - 3)

∣ 3 - 2 x ∣ < 5

- x^{2} - 2 x + 5 = 0

What are the solutions to the equation 4x^2-12x=-13 ?
The solutions to the equation 4x^2-12x=-13 are x= 3/2+i,x= 3/2-i
Find the zeros of 4x^2-12x=-13
The zeros of 4x^2-12x=-13 are x= 3/2+i,x= 3/2-i