What are the solutions to the equation 0=x^2-6x-4 ?

The solutions to the equation 0=x^2-6x-4 are x=3+sqrt(13),x=3-sqrt(13)

Find the zeros of 0=x^2-6x-4

The zeros of 0=x^2-6x-4 are x=3+sqrt(13),x=3-sqrt(13)

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0 = x^{2} - 6 x - 4

x = 3 + 13, x = 3 - 13

Decimal Notation

x = 6.60555 \dots, x = - 0.60555 \dots

Solution steps

0 = x^{2} - 6 x - 4

Switch sides

x^{2} - 6 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 4) = 213

x_{1, 2} = \frac{- ( - 6 ) \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 13}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 13}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 13}{2 \cdot 1} : 3 + 13

x = \frac{- ( - 6 ) - 2 13}{2 \cdot 1} : 3 - 13

The solutions to the quadratic equation are:

x = 3 + 13, x = 3 - 13

5 (\frac{1}{3})

\frac{2}{3} - \frac{1}{8}

0 = - 20 x^{2} + 1900 x - 31000

3 x^{2} = 12 x - 12

What are the solutions to the equation 0=x^2-6x-4 ?
The solutions to the equation 0=x^2-6x-4 are x=3+sqrt(13),x=3-sqrt(13)
Find the zeros of 0=x^2-6x-4
The zeros of 0=x^2-6x-4 are x=3+sqrt(13),x=3-sqrt(13)