What is 1+(4x)/9-1/4 (x+9)>= x ?

The solution to 1+(4x)/9-1/4 (x+9)>= x is x<=-45/29

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1+(4x)/9-1/4 (x+9)>= x

1 + \frac{4 x}{9} - \frac{1}{4} (x + 9) \geq x

x \leq - \frac{45}{29}

Interval Notation

(- \infty, - \frac{45}{29}]

Decimal Notation

x \leq - 1.55172 \dots

Solution steps

1 + \frac{4 x}{9} - \frac{1}{4} (x + 9) \geq x

Move

1

to the right side

\frac{4 x}{9} - \frac{1}{4} (x + 9) \geq x - 1

Multiply by LCM

16 x - 9 (x + 9) \geq 36 x - 36

Expand

- 9 (x + 9) : - 9 x - 81

16 x - 9 x - 81 \geq 36 x - 36

Add similar elements:

16 x - 9 x = 7 x

7 x - 81 \geq 36 x - 36

Move

81

to the right side

7 x \geq 36 x + 45

Move

36 x

to the left side

- 29 x \geq 45

Multiply both sides by

- 1

29 x \leq - 45

Divide both sides by

29

x \leq - \frac{45}{29}

9 m^{2} + 6 m + 1

\frac{y}{8} = 5

12 x^{4} y^{5} (- 10 x^{5} y^{2})

6 + 32

18 = \frac{1}{2} (r)^{2} (0.7)

What is 1+(4x)/9-1/4 (x+9)>= x ?
The solution to 1+(4x)/9-1/4 (x+9)>= x is x<=-45/29