What are the solutions to the equation (1-a)+3(1-a)^2=0 ?

The solutions to the equation (1-a)+3(1-a)^2=0 are a= 4/3 ,a=1

Find the zeros of (1-a)+3(1-a)^2=0

The zeros of (1-a)+3(1-a)^2=0 are a= 4/3 ,a=1

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(1 - a) + 3 (1 - a)^{2} = 0

a = \frac{4}{3}, a = 1

Decimal Notation

a = 1.33333 \dots, a = 1

Solution steps

(1 - a) + 3 (1 - a)^{2} = 0

Expand

(1 - a) + 3 (1 - a)^{2} : 3 a^{2} - 7 a + 4

3 a^{2} - 7 a + 4 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 \cdot 4 = 1

a_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 3}, a_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 3}

a = \frac{- ( - 7 ) + 1}{2 \cdot 3} : \frac{4}{3}

a = \frac{- ( - 7 ) - 1}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

a = \frac{4}{3}, a = 1

26 \cdot 33

x^{2} + 5 x - 24 = 0

\frac{11}{15} = w - \frac{8}{15}

x^{2} + 10 x + 1 \geq 12

1 \leq x

What are the solutions to the equation (1-a)+3(1-a)^2=0 ?
The solutions to the equation (1-a)+3(1-a)^2=0 are a= 4/3 ,a=1
Find the zeros of (1-a)+3(1-a)^2=0
The zeros of (1-a)+3(1-a)^2=0 are a= 4/3 ,a=1