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Popular >

|x+2|<= 8

Solution

∣ x + 2 ∣ \leq 8

Solution

- 10 \leq x \leq 6

+1

Interval Notation

[- 10, 6]

Solution steps

∣ x + 2 ∣ \leq 8

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 8 \leq x + 2 \leq 8

x + 2 \geq - 8 and x + 2 \leq 8

x \geq - 10 and x \leq 6

Merge Overlapping Intervals

- 10 \leq x \leq 6

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\frac{4}{\frac{4}{3}}

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Frequently Asked Questions (FAQ)

What is |x+2|<= 8 ?
The solution to |x+2|<= 8 is -10<= x<= 6