What are the solutions to the equation 11t^2+250=125 ?

The solutions to the equation 11t^2+250=125 are t=(5sqrt(5))/(sqrt(11))i,t=-(5sqrt(5))/(sqrt(11))i

Find the zeros of 11t^2+250=125

The zeros of 11t^2+250=125 are t=(5sqrt(5))/(sqrt(11))i,t=-(5sqrt(5))/(sqrt(11))i

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11 t^{2} + 250 = 125

t = \frac{5 5}{11} i, t = - \frac{5 5}{11} i

Solution steps

11 t^{2} + 250 = 125

Move

250

to the right side

11 t^{2} = - 125

Divide both sides by

11

t^{2} = - \frac{125}{11}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = - \frac{125}{11}, t = - - \frac{125}{11}

- \frac{125}{11} = \frac{5 5}{11} i

- - \frac{125}{11} = - \frac{5 5}{11} i

t = \frac{5 5}{11} i, t = - \frac{5 5}{11} i

\frac{x ^{\frac{1}{3}} y ^{\frac{2}{5}}}{x ^{- \frac{1}{5}} y}

3 x + \frac{3}{2} x = 12.15

- 8 z + 11 = - 10 - 5.5 z

\frac{x ^{2} - 4 x - 12}{x ^{2} - 1} \geq 0

y^{2} + y - 2

What are the solutions to the equation 11t^2+250=125 ?
The solutions to the equation 11t^2+250=125 are t=(5sqrt(5))/(sqrt(11))i,t=-(5sqrt(5))/(sqrt(11))i
Find the zeros of 11t^2+250=125
The zeros of 11t^2+250=125 are t=(5sqrt(5))/(sqrt(11))i,t=-(5sqrt(5))/(sqrt(11))i