What is the answer to 2(y-1)+4y=3(y-1)+7 ?

The answer to 2(y-1)+4y=3(y-1)+7 is y=2

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2(y-1)+4y=3(y-1)+7

2 (y - 1) + 4 y = 3 (y - 1) + 7

y = 2

Solution steps

2 (y - 1) + 4 y = 3 (y - 1) + 7

Expand

2 (y - 1) + 4 y : 6 y - 2

Expand

3 (y - 1) + 7 : 3 y + 4

6 y - 2 = 3 y + 4

Move

2

to the right side

6 y = 3 y + 6

Move

3 y

to the left side

3 y = 6

Divide both sides by

3

y = 2

17 \cdot 5

9 \cdot 49 \cdot 16 + 57 - 3 \cdot \frac{5}{60}

\frac{5}{8} - \frac{3}{8}

5 m + 15

- 4 (x + 6) = - 40

What is the answer to 2(y-1)+4y=3(y-1)+7 ?
The answer to 2(y-1)+4y=3(y-1)+7 is y=2
Solve for y: 2(y-1)+4y=3(y-1)+7
The solution is y=2